vault backup: 2026-07-30 15:49:29
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@@ -216,6 +216,7 @@
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},
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"active": "25f5b25d5eca7203",
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"SS2026/Quantum Computing/Bernstein-Vazirani/Anhänge/Pasted image 20260730154444.png",
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"SS2026/Quantum Computing/Bernstein-Vazirani/Anhänge/Pasted image 20260730153305.png",
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"SS2026/Quantum Computing/Bernstein-Vazirani/Anhänge/Pasted image 20260730145119.png",
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@@ -233,7 +234,6 @@
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"SS2026/Quantum Computing/8. Ket Notation/Anhänge/Pasted image 20260730102305.png",
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"SS2026/Quantum Computing/8. Ket Notation/Anhänge/Pasted image 20260730102024.png",
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"SS2026/Quantum Computing/8. Ket Notation/Anhänge/Pasted image 20260730101723.png",
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"SS2026/Quantum Computing/8. Ket Notation/Anhänge",
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"SS2026/Quantum Computing/8. Ket Notation",
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"SS2026/Quantum Computing/4. Observing and measuring/Observing probabilistic and measuring quantum systems.md",
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@@ -31,3 +31,14 @@ It can be calculated as follows:
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![[Pasted image 20260730153305.png]]
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And we can rewrite $U_f(\ket{x} \otimes \ket{-})$ as
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![[Pasted image 20260730154444.png]]
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The bottom wire has not changed.
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The top wire now has f(x) encoded in its quantum state.
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The phenomenon that the output of f is encoded as a -1 is called phase kickback.
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We need one final step before measuring.
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Now, we perform one final hadamard gate on the top wire.
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