vault backup: 2026-07-29 10:53:22
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+16
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A photon in the up state $\begin{pmatrix} 1 \\ 0 \end{pmatrix}$ is sent through the first beam splitter.
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A photon in the up state $\begin{pmatrix} 1 \\ 0 \end{pmatrix}$ is sent through the first beam splitter.
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Afterwards the photon is in the state $\begin{pmatrix} \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \end{pmatrix}$
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Afterwards the photon is in the state $\begin{pmatrix} \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \end{pmatrix}$
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So the photon is in a superposition between up and down, so between passing through the box with maybe a bomb and passing through empty air.
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It makes a difference whether a bomb is inside the box or not!!
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First, what happens if there is no bomb:
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Photon can pass through both paths.
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Second beam splitter is reached in any case.
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After the second splitter the photon is in the state : $B(\begin{pmatrix} \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \end{pmatrix})$ = $\begin{pmatrix} 1 \\ 0 \end{pmatrix}$
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After measuring we get the following distribution:
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![[Pasted image 20260729105142.png]]
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Now, what happens if there is a bomb:
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1. [[Introduction]]
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