diff --git a/.obsidian/workspace.json b/.obsidian/workspace.json index 5257637..6132760 100644 --- a/.obsidian/workspace.json +++ b/.obsidian/workspace.json @@ -216,6 +216,7 @@ }, "active": "25f5b25d5eca7203", "lastOpenFiles": [ + "SS2026/Quantum Computing/Bernstein-Vazirani/Anhänge/Pasted image 20260730145119.png", "SS2026/Quantum Computing/Bernstein-Vazirani/Anhänge/Pasted image 20260730144713.png", "SS2026/Quantum Computing/Bernstein-Vazirani/Anhänge", "SS2026/Quantum Computing/Introduction to Quantum Computing.md", @@ -235,7 +236,6 @@ "SS2026/Quantum Computing/8. Ket Notation/Anhänge/Pasted image 20260730101012.png", "SS2026/Quantum Computing/8. Ket Notation/Anhänge", "SS2026/Quantum Computing/8. Ket Notation", - "SS2026/Quantum Computing/7. Quantum Circuits/Anhänge/Pasted image 20260730092817.png", "SS2026/Quantum Computing/4. Observing and measuring/Observing probabilistic and measuring quantum systems.md", "SS2026/Quantum Computing/5. Partial observing and measuring/Partial observing and measuring systems.md", "SS2026/Quantum Computing/6. Composite Systems/Composite Systems.md", diff --git a/SS2026/Quantum Computing/Bernstein-Vazirani/Anhänge/Pasted image 20260730145119.png b/SS2026/Quantum Computing/Bernstein-Vazirani/Anhänge/Pasted image 20260730145119.png new file mode 100644 index 0000000..5e8633a Binary files /dev/null and b/SS2026/Quantum Computing/Bernstein-Vazirani/Anhänge/Pasted image 20260730145119.png differ diff --git a/SS2026/Quantum Computing/Bernstein-Vazirani/Bernstein-Vazirani Algorithm.md b/SS2026/Quantum Computing/Bernstein-Vazirani/Bernstein-Vazirani Algorithm.md index e0b9e22..47d0ec0 100644 --- a/SS2026/Quantum Computing/Bernstein-Vazirani/Bernstein-Vazirani Algorithm.md +++ b/SS2026/Quantum Computing/Bernstein-Vazirani/Bernstein-Vazirani Algorithm.md @@ -12,4 +12,10 @@ We will look at a quantum algorithm that will find s with only one evaluation of The top wire consists of n qubits in state 0. $\ket{0}^n = \ket{0} \otimes ... \otimes \ket{0}$ The bottom wire is in state 1. -Both wires together are in state $\ket{0^n1} = \ket{0}^n \$ \ No newline at end of file +Both wires together are in state $\ket{0^n1} = \ket{0}^n \otimes \ket{1}$ + +First, we apply the Hadamard gate on all qubits. +The resulting state is calculated as follows: + +![[Pasted image 20260730145119.png]] +